PLEASE HELP In the figure below, ∠DEC ≅ ∠DCE, ∠B ≅ ∠F, and DF ≅ BD. Point C is the point of intersection between AG and BD while point E is the point of intersection between AG and DF. Prove ΔABC ≅ ΔGFE.

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∠ABC ≅ ∠DEC

∠DEC = ∠GEF

thus:

∠ABC = ∠GEF

∠GFE ≅ ∠DCE

∠DCE = ∠ACB

thus:

∠ACB = ∠GFE

If two of their angles are equal, then the third angle must also be equal, because angles of a triangle always add to make 180°.

Thus: ΔABC ∼ ΔGEF by AA similar triangle postulate.

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ItsNobody~ ☆

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Step-by-step explanation: