PLEASE HELP ME I AM TIMED ONLY HAVE !% more minutes :( PLEASE I WILL GIVE BRAINIEST Table sugar is sucrose (C12H22O11). Determine the percentage composition by mass of sucrose.?

Look up the atomic masses of each element in sucrose:

• C has an atomic mass of 12.011 u

• H has an atomic mass of 1.008 u

• O has an atomic mass of 15.999 u

Sucrose consists of 12 C atoms, 22 H atoms, and 11 O atoms, so one molecule has an atomic mass of about

12 (12.011 u) + 22 (1.008 u) + 11 (15.999 u) ≈ 342.3 u

Then

• C makes up (12 (12.011 u)) / (342.3 u) ≈ 0.4211 = 42.11%,

• H makes up (22 (1.008 u)) / (342.3 u) ≈ 0.06479 = 6.479%, and

• O makes up (11 (15.999 u)) / (342.3 u) ≈ 0.5141 = 51.41%

of sucrose

B.

Step-by-step explanation:

We have to find that which graph has horizontal asymptote at 4

We know that to find the horizontal asymptote , we simply evaluate the limit of the function as it approaches to infinity or it approaches to negative infinity.

A.

Limit of function does not exits, so function have not horizontal asymptote.

B.

Because

Hence, function have horizontal asymptote at 4.

C.

Hence, function have not horizontal asymptote.

D.

Because

Hence, function have horizontal asymptote at -4.

Therefore, option B is true.