Please help me i need this before Wednesday , will mark brainiliest and I don’t know how to solve it

The price of one adult ticket is $11 and the price of one student ticket is $6.

Step-by-step explanation:

We can write a system of equations to represent the situation. Let a represent the price of adult tickets sold and s represent the price of student tickets.

On the first day, nine adult tickets and 12 student tickets were sold for a total of $171. Hence:

And on the second day, 13 adult tickets and 14 student tickets were sold for a total of $227. Hence:

This yields a system of equations:

We can solve using elimination. Note that the LCM of 12 and 14 is 84. Hence, we can multiply the first equation by -7 and the second by 6:

Adding the two equations together now produces:

Therefore, the price of one adult ticket is $11.

To find the price of one student ticket, use either one of the original equations:

In conclusion, the price of one adult ticket is $11 and the price of one student ticket is $6.

3x + 1 = y
2x + 3y = 14

To solve this system of equations, we are going to use the substitution method.  Substitution the equation where the variable is isolated into the second equation.  In this system of equations, y is isolated, so we will replace y in the second equation with 3x + 1.

2x + 3y = 14
2x + 3(3x + 1) = 14
2x + 9x + 3 = 14
We will add the like terms and subtract 3 from both sides of the equation.
11x + 3 = 14
11x = 11
x = 1
In this system of equations, x is equal to 1.  Now we will go back and solve for y, plugging in 1 for x.
3(1) + 1 = y
2(1) + 3y = 14

3 + 1 = y
2 + 3y = 14

4 = y
3y = 2

4 = y
4 = y

The solution to this system of equations is (1, 4).