PLEASE HELP ME I REALLY NEED TO GET THIS RIGHT - id9376443, mubasharshafiq1583

Question

Mathematics: PLEASE HELP ME I REALLY NEED TO GET THIS RIGHT PLEASE SOMEONE HELP ON THIS PLEASE

mubasharshafiq1583 · Accepted Answer

Remember that the vertex form of a parabola is f(x)=a(x-h)^2+k where (h,k) is the vertex of the parabola.

Now, to find the vertex of the parabola, we are going to use the vertex formula:

For a quadratic of the form f(x)=ax^2+bx+c , the vertex (h,k) is given by:

$h=\frac{-b}{2a}$

k=f(h) in other words, we find by evaluating the function at

We know form our quadratic that a=6 and b=12 , so let's use our formula to find :

$h=\frac{-b}{2a}$

$h=\frac{-12}{2(6)}$

$h=\frac{-12}{12}$

h=-1

Now we can evaluate our function at to find :

f(x)=6x^2+12x-10

k=f(-1)=6(-1)^2+12(-1)-10

k=f(-1)=6-12-10

k=f(-1)=-16

k=-16

Now, we can rewrite our parabola in vertex form:

f(x)=a(x-h)^2+k

h=-1 , k=-16 , and a=6

f(x)=6(x-(-1))^2+(-16)

f(x)=6(x+1)^2-16

We can conclude that the correct answer is: y = 6(x + 1)2 – 16

PLEASE HELP ME I REALLY NEED TO GET THIS RIGHT PLEASE SOMEONE HELP ON THIS PLEASE