Please help me with this question

  -3i +-12j

Step-by-step explanation:

P2 -P1 = (-1-2, -6-6) = (-3, -12)

In terms of unit vectors i and j, this is -3i -12j.

a) equation: y = mx + b        y = - x -5

b) equation: y = x - 5

Step-by-step explanation:

x + y = 3   i.e. y = - x + 3

slope(m) = - 1

a) parallel line: slope (m') = -1

pass (3 , - 8)   y intercept (b) = y - mx = -8 - (-1)x3 = -8 + 3 = -5

equation: y = mx + b        y = - x -5

b) perpendicular line slope = - 1/m = 1

pass (4 , - 1)   y intercept (b) = - 1 - (1 x 4) = - 5

equation: y = x - 5