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joshualoz5414
26.06.2020 •
Mathematics
Please help :( really need answer
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Ответ:
Options (C) and (F)
Step-by-step explanation:
Polynomial function is,
f(x) = x³ - x² - 5x - 3
Possible rational roots of the given function will be =![\frac{\pm1, \pm3}{\pm1}](/tpl/images/0694/7706/3ece1.png)
By putting x = -1
f(-1) = (-1)³ - (-1)² -5(-1) - 3
= -1 - 1 + 5 - 3
= 0
Therefore, x = -1 will a root of the given function.
Now we apply synthetic division to get the other roots,
-1 | 1 -1 -5 -3
↓ -1 2 3
1 -2 -3 0
Therefore, factored form of the polynomial will be (x + 1)(x² - 2x - 3).
Now we will find the roots of (x² -2x - 3).
x² - 2x - 3 = x² - 3x + x - 3
= x(x - 3) + 1(x - 3)
= (x + 1)(x - 3)
For roots of the function, f(x) = 0
(x + 1)(x - 3) = 0
x = -1, 3
Therefore, roots of the function are x = -1, 3
Options (C) and (F) are the answers.
Ответ:
Step-by-step explanation:
to find the slope, we can take any two points, and find the slope between then
e.g.
(0, -3) and (20, 2) =>![m = \frac{y_2-y_1}{x_2-x_1} = \frac{2-(-3)}{20-0} = \frac{1}{4}](/tpl/images/0853/9424/6d162.png)
now we can test other points, and if the slopes are consistent, we can determine the overall slope
(4, -2) and (16, 1) =>![m = \frac{y_2-y_1}{x_2-x_1} = \frac{1-(-2)}{16-4} = \frac{1}{4}](/tpl/images/0853/9424/99640.png)
(8, -1) and (12, 0) =>![m = \frac{y_2-y_1}{x_2-x_1} = \frac{0-(-1)}{12-8} = \frac{1}{4}](/tpl/images/0853/9424/e0396.png)
yep, it's consistent
the slope is![\frac{1}{4}](/tpl/images/0853/9424/0d86b.png)