Mathematics: Please help solve for correct answer

Line v has equation y = 2x+1======line u has equation [tex]y=2x+6[/tex] and it is parallel to line v.line u has a slope of 2.parallel lines have the same slope; therefore, line v also has a slope of 2.the point-slope equation of a line with a slope [tex]m[/tex] and a point on the line [tex](x_1,y_1)[/tex] is [tex]y - y_1 = m(x-x_1)[/tex]let s fit this to line v.since the slope of line v is 2, [tex]m=2[/tex] [tex]y - y_1 = 2(x-x_1)[/tex]since line v has the point [tex](-1,-1)[/tex], [tex]x_1 = -1[/tex]...

Please help solve for correct answer - id12084695, stephaniero6

Ответ:

mvazquez298

20.03.2021

Mathematics

Here's link to the

cutt.ly/zxt1ipy

0,0(0 оценок)

Ответ:

afridi5250

23.12.2021

Mathematics

Line v has equation y = 2x+1======line u has equation $y=2x+6$ and it is parallel to line v.line u has a slope of 2.parallel lines have the same slope; therefore, line v also has a slope of 2.the point-slope equation of a line with a slope $m$ and a point on the line $(x_1,y_1)$ is $y - y_1 = m(x-x_1)$ let's fit this to line v.since the slope of line v is 2, $m=2$ $y - y_1 = 2(x-x_1)$ since line v has the point $(-1,-1)$ , $x_1 = -1$ and $y_1 = -1$ $y - (-1) = 2())$ subtracting by a negative number is the same as adding $y + 1 = 2(x+1)$ technically you are done, but if you want point-slope form: you can distribute the 2 inside the parentheses. $\begin{aligned} y + 1 & = 2(x+1) \\ y + 1 & = 2x + 2 \end{aligned}$ subtract 1 from both sides $\begin{aligned} y & = 2x + 2 - 1 \\ y & = 2x + 1 \end{aligned}$ line v has equation y = 2x+1

0,0(0 оценок)

Please help solve for correct answer

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Mathematics

Ask an AI advisor a question

Please help solve for correct answer​

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Mathematics

Ask an AI advisor a question

Please help solve for correct answer