carterkanye468
24.12.2020 •
Mathematics
PLEASE HELP
The relationship between altitude and the boiling point of a liquid is linear. At an altitude of 8200 ft, the liquid boils at 199.42°F. At an altitude of 4700 ft, the liquid boils at 206.07°F. Write an equation giving the boiling point b of the liquid, in degrees Fahrenheit, in terms of altitude a, in feet. What is the boiling point of the liquid at 2500 ft?
Write an equation.
b=
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Ответ:
b=-0.0019a + 215
at 2500 ft, b=210.25 degrees F
Step-by-step explanation:
First find the slope. a=altitude, b = temperature
slope is b2-b1 / a2-a1
points are (8200, 199.42) and (4700, 206.07)
(206.07 - 199.42) / (4700-8200)
= 6.65/ -3500
= - 0.0019
we have b = -0.0019a + intercept
plug in a point to find intercept
199.42 = -0.0019*8200 + intercept
intercept = 199.42 + 15.58 = 215
b=-0.0019a + 215
at a=2500 ft, substitute into equation
b= -0.0019*2500 + 215
= -4.75 + 215
= 210.25 degrees F
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Ответ:
no
Step-by-step explanation:
because x+X+X+X is adding and 4x is 4 multiplied times x therefore no they are not equivalent