Please help this is due today

Show work please

↓↓↓Btw sorry its not in order

Step-by-step explanation:

m∠62 and ∠g are vertical angles so they're congruent.

∠g = 62°

∠f and m∠62 are linear pairs so they're supplementary

∠f + 62 = 180

∠f = 118°

∠e is a right angle and is supplementary to a 90° angle

∠e = 90°

Adding ∠e, m∠28° and the missing angle should sum up to 180° since its a triangle. x = missing angle

x + ∠e + m∠28 = 180°

x + 90 + 28 = 180

x + 118 = 180

x = 62°

∠h ≅ x

∠h ≅ 62

∠h = 62°

∠b and m∠28 are vertical angles so they're congruent.

∠b ≅ m∠28

∠b = 28°

∠b and ∠a are linear pairs so they are supplementary.

∠a + ∠b = 180

∠a + 28 = 180

∠a = 152°

∠c and ∠a are corresponding angles so they're congruent.

∠c ≅ ∠a

∠c ≅ 152

∠c = 152°

∠c and ∠j are vertical angles so they're congruent.

∠j ≅ ∠c

∠j ≅ 152

∠j = 152°

The corresponding angle of c is 152° as well. Let's call it y. Y corresponds to the angle with a bisector. Call that whole angle z.

z ≅ y

z ≅ 152

z = 152°

Z has a bisector meaning the two angles that formed because of the bisector are congruent.

∠d and the other angle add up to 152°. They're equal.

∠d = 152 ÷ 2

∠d = 76°

Hope I helped!

9

Step-by-step explanation:

n=3, a=729

For any odd integer, n ; a will have only one real nth root which will be a positive integer.

Similarly, for any integer, n, that is > 1 ; related by the expression ;

p^n = a ; the nth root of a = p

Therefore,

If n = 3 ; a = 729

p^3 = 729

To obtain the value of p ; take the cube of both sides

(p^3)*1/3 = 729^1/3

p = 9

Hence, the real nth root of 729 is +9 when n = 3