Please help with last 2 domain and range

See below for answers and explanations

Step-by-step explanation:

Top left: Since y can't be greater than 0 but is equal to 0, then the range is (-∞,0] and the domain is (-∞,∞) since there are no domain restrictions

Top right: Since both x and y have no restrictions, then the domain is (-∞,∞) and the range is (-∞,∞)

Bottom left: Since y cannot be less than 2 but equal to it, and x holds no domain restrictions, then the domain is (-∞,∞) and the range is [2,∞)

Bottom right: Since both x and y have no restrictions, then the domain is (-∞,∞) and the range is (-∞,∞)

Sine rule states that the ratio of a side of a triangle to the angle opposite the side is equivalent for all 3 sides and their respective opposite angles.

Thus, the side opposite ∠B is side AC, which is 10 units long. The side opposite ∠A is side BC, which is 8 units long. Substitute these values into the formula. (We are at line 2 of working)

Line 3: multiply both sides by 10 to find sinB

This would give us

This is can also be written as: (as seen in line 4)

To find the measure of angle B:

~ Explanation for line 6 and onwards~

The sine of an angle is positive in quadrants I and II. Since sinB is positive (≈0.69899), we are looking at these 2 quadrants. Since the reference angle is 44° rounded off to the nearest whole degree, in quadrant I, the angle would be 44° too.

In quadrant 2, the angle would be 180° -44°= 136°.