Please help with the answer below

Anika is correct

Step-by-step explanation:

* Lets revise the rules of reflection and rotation

- If point (x , y) reflected across the x-axis  then its image is (x , -y)

- If point (x , y) rotated about the origin by angle 270° clock wise  then

 its image is (-y , x)

* Lets check the vertices of the two triangles

- The vertices of Δ ABC are:

# A (-7 , 2)

# B (-3 , 6)

# C (-2 , 1)

- The vertices of Δ PRQ

# P (-7 , -2)

# R (-3 , -6)

# Q (-2 , -1)

* By comparing between the vertices of the two triangles

∵ Each y-coordinates of Δ PRQ has opposite sign of each

   y-coordinates of Δ ABC

∵ All x-coordinates of Δ PRQ are the same with x-coordinates of

  Δ ABC

- That means Δ PRQ is the image of Δ ABC after reflection across

  the x-axis  

∵ Reflection doesn't change the shape and the size of the figure

∴ Δ ABC and Δ PRQ have same size (equal sides and equal angles)

∴ Δ ABC is congruent to Δ PRQ

* Anika is correct