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kailinaguilar2187
07.07.2021 •
Mathematics
Please hlep x^2+6x+1=0
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Ответ:
x = - 3 ± 2![\sqrt{2}](/tpl/images/1390/3259/7e821.png)
Step-by-step explanation:
Given
x² + 6x + 1 = 0 ( subtract 1 from both sides )
x² + 6x = - 1
Using the method of completing the square
add/ subtract ( half the coefficient of the x- term)² to both sides
x² + 2(3)x + 9 = - 1 + 9
(x + 3)² = 8 ( take the square root of both sides )
x + 3 = ±
= ± 2
( subtract 3 from both sides )
x = - 3 ± 2![\sqrt{2}](/tpl/images/1390/3259/7e821.png)
Then
x = - 3 - 2
, x = - 3 + 2![\sqrt{2}](/tpl/images/1390/3259/7e821.png)
Ответ:
each kid gets 2 cookies because there is usually 20 kids in a class