PLEASE HURRY AND HELP The sum of 5 consecutive numbers is 70. Determine the value of the smallest number.

Work Shown:

x = first number

x+1 = second number

x+2 = third number

x+3 = fourth number

x+4 = fifth number

Note how the numbers are one after another. Consecutive numbers follow this pattern. For example: 6,7,8,9,10 are consecutive numbers. One number follows right after the other.

Add up those five expressions. Set the sum equal to 70 and solve for x

(x)+(x+1)+(x+2)+(x+3)+(x+4) = 70

(x+x+x+x+x)+(1+2+3+4) = 70

5x+10 = 70

5x = 70-10

5x = 60

x = 60/5

x = 12 is the first number and the smallest number

x+1 = 12+1 = 13 is the second number

x+2 = 12+2 = 14 is the third number

x+3 = 12+3 = 15 is the fourth number

x+4 = 12+4 = 16 is the fifth number

Check:

12+13+14+15+16 = 70

which confirms our answer

You could use a guess and check method, but the algebraic approach is much more efficient.

my guess would be c. but id wait for someone else to answer just to be sure