Mathematics: PLEASE I NEED HELP I need someone who is actually good at this!!

Step-by-step explanation:step 1;-Given now you have rationalizing denominator (i.e monomial) with By using algebraic formula is ......(a)now ....(1)again using Formula now simplification , we get denominator functionagain you have to simplify numerator termnow simplify cancelling y and 2 valueswe get Final answer...

PLEASE I NEED HELP I need someone who is actually

Ответ:

ronaldotheexplorer12

24.11.2021

Mathematics

#8= B

#6= C

#7= D

#9= C

#10= A

Step-by-step explanation:

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Ответ:

djdkfkfkckmfmf7724

24.11.2021

Mathematics

[First one, aka #8] c

- subtract 7x from both sides

- divide by 5

- slope is m is y = mx + b

[Second one, aka #7] is d

- subtract 2x from both sides

- divide by 5

- find the negative reciprocal

[Third one, aka #6] is c

- will have a slope of 2 since it is parallel

- plug the point into y = 2x + b and solve for b

[Fourth one, aka #9] is a

- change in d over change in c

- 29 - 20 / 6 - 0 = 9/6 = 3/2

[Fifth one, aka #10] is b

- I created the system:

2h + m = 2.85

3h + 2m = 4.45

- Because he had two hotdogs (2h) and one milk (m), and then 3 hotdogs (3h) and 2 milk (2m) so option b matches the best

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

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Ответ:

cia029587691

31.05.2022

Mathematics

$\frac{\sqrt[3]{90 x^2 y z^2} }{6 y z}$

Step-by-step explanation:

step 1;-

Given $\frac{\sqrt[3]{5 x^2} }{\sqrt[3]{12 y^2 z} }$

now you have rationalizing denominator (i.e monomial) with

$\frac{\sqrt[3]{5 x^2} }{\sqrt[3]{12 y^2 z} } X \frac{\sqrt[3]{(12 y^2 z)^{2} } }{\sqrt[3]{(12 y^2 z)^2} }$

By using algebraic formula is

$\sqrt{ab} = \sqrt{a} \sqrt{b}$ ......(a)now $\frac{\sqrt[3]{5 x^2)(12 y^2 z)^2} }{\sqrt[3]{12 y^2 z)(12 y^2 z)^2} }$ $\frac{\sqrt[3]{720 x^2 y^4 z^2} }{\sqrt[3]{(12 y^2 z)^{3} } }$ ....(1)again using Formula $\sqrt[n]{a^{n} } =a$

now simplification , we get denominator function

$\frac{\sqrt[3]{720 x^2 y^4 z^2} }{12 y^2 z}$

again you have to simplify numerator term

$\frac{\sqrt[3]{2^3 y^3 90 (x^2 y z^2)} }{12 y^2 z}$

now simplify

$\frac{2 y\sqrt[3]{90 x^2 y z^2} }{12 y^2 z}$

cancelling y and 2 values

we get Final answer

$\frac{\sqrt[3]{90 x^2 y z^2} }{6 y z}$

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PLEASE I NEED HELP I need someone who is actually good at this!!

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