![morgaaaan651](/avatars/48992.jpg)
morgaaaan651
16.04.2021 •
Mathematics
Please solve! I need this for a test.
Solved
Show answers
More tips
- H Health and Medicine How to perform artificial respiration?...
- H Health and Medicine 10 Tips for Avoiding Vitamin Deficiency...
- F Food and Cooking How to Properly Cook Buckwheat?...
- F Food and Cooking How Many Grams Are In a Tablespoon?...
- L Leisure and Entertainment Carving: History and Techniques for Creating Vegetable and Fruit Decorations...
- P Photography and Videography How to Choose the Perfect Photo Paper for Your Images?...
- H Health and Medicine What vaccines do children need?...
- H Health and Medicine Reasons for the Appearance of Warts: Everything You Need to Know...
- A Art and Culture How to Learn Screaming: Step-by-Step Guide for Beginners...
- H Health and Medicine Contraceptive Pills After 35: The Importance Of Choosing The Right Medication...
Answers on questions: Mathematics
- M Mathematics Need help please help...
- M Mathematics What begins with e, ends with e, and contains 1 letter? btw this is totally a math question and it isn t here because there is no section i can find that fits this...
- M Mathematics Solve equation by completing the square...
- M Mathematics Simplify the expression. 5(3f – 8g) + 2g...
- M Mathematics The time t required to do a job varies inversely as the number of people working. it takes 2 hr for 5 cooks to prepare the food for a wedding rehearsal dinner. how long...
- M Mathematics What is the circumstance of the trampoline including its outer edge? use 3.14 for pie...
- M Mathematics Line 2 should read -6.5q-3=23. enter the solution to the equation. q=?...
- M Mathematics What is this and why dont i know the answer...
- M Mathematics −−→ lo bisects ∠ nlm , lm = 18 , no = 4 , and ln = 10 . lo → bisects ∠ nlm , lm = 18 , no = 4 , and ln = 10 . what is the value of x?...
- M Mathematics If AM = 2x + 3 and CP = x + 4, find x and AM....
Ответ:
The standard deviation of the number of rushing yards for the running backs that season is 350.
Step-by-step explanation:
Consider the provided information.
The mean number of rushing yards for the running backs that season is 790 yards. One running back had 1,637 rushing yards for the season, which is 2.42 standard deviations above the mean number of rushing yards.
Here it is given that mean is 790 and 1637 is 2.42 standard deviations above the mean.
Use the formula:![z=\frac{x-\mu}{\sigma}](/tpl/images/0309/0746/c2a86.png)
Here z is 2.42 and μ is 790, substitute the respective values as shown.
Hence, the standard deviation of the number of rushing yards for the running backs that season is 350.