svalencia2
03.12.2020 •
Mathematics
PLLSS HELP DUE IN 3 MINTUES!!
Given the function h(x)=x^2+10x+21h(x)=x
2
+10x+21, determine the average rate of change of the function over the interval -10\le x \le -3−10≤x≤−3.
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Ответ:
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Ответ:
2. (-6,-4) is x1,y1 and (4,-6) is x2,y2
3. y-(-4) = m(x-(-6)
m is the gradient, 10/10, which is 1. make two negatives into a positive.
4. y+4 = x+6
therefore the equation of the lines is y = x+2
substitute the points back into the equation to double check.