Mathematics: Pls explain your answer. Thanks in advance. I will mark brainliest if u explain

10-5Step-by-step explanation:As per the attached figure, right angled has an inscribed circle whose center is .We have joined the incenter to the vertices of the . Sides MD and DL are equal because we are given that Formula for area of a As per the figure attached, we are given that side a = 10.Using pythagoras theorem, we can easily calculate that side ML = 10Points P,Q and R are at on the sides ML, MD and DL respectively so IQ, IR and IP are heights of MIL, MID and DIL.Also, So, radius of circle...

Pls explain your answer. Thanks in advance. I will

Ответ:

vzimokha

19.03.2022

Mathematics

Step-by-step explanation:

Using Trigonometry,

tan33° = Opposite/Adjacent = GF/DF.

Therefore GF = DF * tan33°

= 235tan33° = 152.6.

Angle GEF = Angle EDG + Angle DGE

= 33° + 34° = 67°. (Exterior Angle Theorem)

Using Trigonometry,

sin67° = Opposite/Hypotenuse = GF/EF.

Therefore EF = GF / sin67°

= 152.6 / sin67° = 165.8.

Hence the answer is the 1st option.

0,0(0 оценок)

Ответ:

camilaird

11.03.2021

Mathematics

10-5 $\sqrt{2}$

Step-by-step explanation:

As per the attached figure, right angled $\triangle MDL$ has an inscribed circle whose center is .

We have joined the incenter to the vertices of the $\triangle MDL$ .

Sides MD and DL are equal because we are given that $\angle M = \angle L = 45 ^\circ.$

Formula for area of a $\triangle = \dfrac{1}{2} \times base \times height$

As per the figure attached, we are given that side a = 10.

Using pythagoras theorem, we can easily calculate that side ML = 10 $\sqrt{2}$

Points P,Q and R are at $90 ^\circ$ on the sides ML, MD and DL respectively so IQ, IR and IP are heights of $\triangle$ MIL, $\triangle$ MID and $\triangle$ DIL.

Also,

$\text {Area of } \triangle MDL = \text {Area of } \triangle MIL +\text {Area of } \triangle MID+ \text {Area of } \triangle DIL$

$\dfrac{1}{2} \times 10 \times 10 = \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10\sqrt2\\\Rightarrow r = \dfrac {10}{2+\sqrt2} \\\Rightarrow r = \dfrac{5\sqrt2}{\sqrt2+1}\\\text{Multiplying and divinding by }(\sqrt2 +1)\\\Rightarrow r = 10-5\sqrt2$

So, radius of circle = $10-5\sqrt2$

Given: Triangle MDL Circle O is inscribed in triangle m∠M=m∠L=45° MD = 10 Find: the radius of the c

0,0(0 оценок)

Pls explain your answer. Thanks in advance. I will mark brainliest if u explain

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Mathematics

Ask an AI advisor a question