Pls help A rectangular floor tile is shown it dimensions are given to the nearest 0.1 metres the tile is only able to sustain maximum pressure of 200 newtons per square metre correct to the nearest 5N/m² given that pressure=Force area. Work out the maximum force in newtons that can safely be applied to the tile.
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Step-by-step explanation:

Force = pressure * area

= 200 * 3.7

= 740 N

maxium force = 785.2

Step-by-step explanation:

1.6m lower bound = 1.55

2.3m lower bound = 2.25

lower bound area = 1.55×2.25=3.4875

lower upper bound = 1.65×2.35=3.8775

pressure upper bound=202.5

pressure lower bound=197.5

202.5×3.8775=785.19375

197.5×3.4875=688.78125

force upper bound = 785.2

force lower bound = 688.8

gets you full marks

Hey there!

FIRST: you have to SIMPLIFY BOTH SIDES of your given EQUATION (there’s approximately 3 ways but we will use 2)

• 3u = 64 – 5u

• 3u = –5u + 64

SECOND: ADD by 5u on BOTH SIDES

• 3u + 5u = –5u + 64 + 5u

• CANCEL: –5u + 5u because that gives you 0

• KEEP: 3u + 5u because it can help us solve for you u-value

“3u + 5u = 8u”

New equation: 8u = 64

THIRD: DIVIDE by 8 on BOTH SIDES

• 8u/8 = 64/8

• CANCEL out: 8u/8 because that gives you 1

• KEEP: 64/8 because that gives you your u-value

“64/8 = u”

“64/8 = 8”

• Therefore your ANSWER: u = 8 ☑️

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)