Pls help meee What is the equation of a line with points (3, 1) and (4, 4) on the line? Express the equation in the form of
= mx + b

Y= -5x + 16

the equation of a line in
slope-intercept form
is.
∙
x
y
=
m
x
+
b
where m is the slope and b the y-intercept
to calculate m use the
gradient formula
∙
x
m
=
y
2
−
y
1
x
2
−
x
1
let
(
x
1
,
y
1
)
=
(
3
,
1
)
and
(
x
2
,
y
2
)
=
(
4
,
−
4
)
⇒
m
=
−
4
−
1
4
−
3
=
−
5
1
=
−
5
⇒
y
=
−
5
x
+
b
←
is the partial equation
to find b substitute either of the 2 given points into

the partial equation
using
(
3
,
1
)
then
1
=
−
15
+
b
⇒
b
=
1
+
15
=
16
⇒
y
=
−
5
x
+
16
←
equation of line

konel òh pè yà= tohalà

Step-by-step explanation:

toala mr thaa ko no