Mathematics: Plss help me do this

(5x^2 + x - 4)(x + 2) = x(5x^2 + x - 4) + 2(5x^2 + x - 4) = 5x^3 + x^2 - 4x + 10x^2 + 2x - 8 = 5x^3 + 11x^2 - 2x - 8...

Plss help me do this - id7117145, josephcfaucett2863

Ответ:

jennifermsalzo

30.01.2022

Mathematics

x1 = -5

x2 = 3

Step-by-step explanation:

You have the following equation:

$\frac{6}{x}-\frac{4}{5}=\frac{2x}{5}$ (1)

To find the solutions of the equation (1) you first eliminate the denominators of the equation, by multiplying the m.c.m, which is 5x, as follow:

30-4x=2x^2

Next, you write the previous equation in the general form ax^2 +bx+c=0, as follow:

2x^2+4x-30=0

Next, you use the quadratic formula to find the solutions:

$x_{1,2}=\frac{-b\pm \sqrt{b^2-4(a)(c)}}{2a}\\\\a=2;\ \ b=4;\ \ c=-30\\\\x_{1,2}=\frac{-4\pm \sqrt{4^2-4(2)(-30)}}{2(2)}\\\\x_{1,2}=\frac{-4\pm16}{4}\\\\x_1=-5\\\\x_2=3$

Then, the solutions for the given equation are x1=-5 and x2=3

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