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mariaaking1413
13.07.2019 •
Mathematics
Plz #30 plz explain ![\sqrt{200 {x}^2 {y}^2 {z}^2](/tex.php?f= \sqrt{200 {x}^2 {y}^2 {z}^2)
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Ответ:
For number 30, its easier if its broken down so were going to make it √200*x^2*y^2*z^2. We can't get a square root of 200 so we will break it into 100*2 to get √2*100*x^2*y^2*z^2. Now let's look at what we can take the square roots of. 2 doesn't have a nice sq. rt. so we will leave it there. 100 has the rt. of 10 so we can make 10√2*x^2*y^2*z^2. X^2 has the root x and we can follow this with the other variables to get 10xyz√2. There is your final simplified answer.
Ответ: