Plz! evaluate the following definite integral: [tex]\int\limits^a_{-a}

Ответ:

owlgirl554

10.03.2022

Just use the power rule:

$\displaystyle\int_{t=-a}^{t=a}(a^2-t^2)\,\mathrm dt=a^2t-\dfrac13t^3\bigg|_{t=-a}^{t=a}$

We also could have use the fact that the integrand is even to write

$\displaystyle\int_{t=-a}^{t=a}(a^2-t^2)\,\mathrm dt=2\int_{t=0}^{t=a}(a^2-t^2)\,\mathrm dt=2\left(a^2t-\dfrac13t^3\bigg|_{t=0}^{t=a}\right)$

I'll continue with this expression since it's easier to evaluate (if only a little):

$2a^3-\dfrac23a^3=\dfrac43a^3$

0,0(0 оценок)

yungking1329

22.05.2020

difficult dial do so ci do do do so do do so do do do

0,0(0 оценок)