Plz help asap will give crown

-18

Step-by-step explanation:

did the problem rn

The 80% confidence interval for the population mean is (2.156, 2.394).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 7

80% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 7 degrees of freedom(y-axis) and a confidence level of . So we have T = 1.415

The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 2.275 - 0.119 = 2.156

The upper end of the interval is the sample mean added to M. So it is 2.275 + 0.119 = 2.394

The 80% confidence interval for the population mean is (2.156, 2.394).