PLZ HELP
Find x in this 45°-45°-90° triangle
x =
is a right triangle the legs are 1.2 with a 45 degree hypotenuse

Step-by-step explanation:

with a 45-45-90 triangle the hypotenuse is equal to the length of one of the legs times the square root of 2.

if one of the legs is 1.2 than the hypotenuse of this triangle should be

1.2* sqrt(2) = about 1.7

p = -4, q = -3

Step-by-step explanation:

y = -2x +4  ... (1)   perpendicular bisector of AB, slope = -2

slope of AB = 1/2

Line AB pass (8,3): (y-3) / (x-8) = 1/2

AB equation: y-3 = 1/2(x-8)      y = 1/2x - 1  ... (2)

(2)-(1): 5/2 x = 5      x = 2

y = 0       (2,0) intercept of bisector and AB, it is midpoint of A (8,3) and (p,q)

(8+p)/2 = 2

p = -4

(3+q)/2 = 0

q = -3