Plz solve this question immediately

Squaring both sides
squaring both sides

cos2+sin2+2cossin=1
cos
2
A
+
sin
2
A
+
2
cos
A
sin
A
=
1

⟹1+2cossin=1⟹2cossin=0
⟹
1
+
2
cos
A
sin
A
=
1
⟹
2
cos
A
sin
A
=
0

⟹−2cossin=0⟹1−2cossin=1
⟹
−
2
cos
A
sin
A
=
0
⟹
1
−
2
cos
A
sin
A
=
1

⟹cos2+sin2−2cossin=1
⟹
cos
2
A
+
sin
2
A
−
2
cos
A
sin
A
=
1

⟹(cos−sin2)=1
⟹
(
cos
A
−
sin
A
2
)
=
1

⟹cos−sin=±1

i like the humor so the answer is a

Step-by-step explanation: