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chy2313
07.10.2019 •
Mathematics
Point a is locatee at (2,8) and point b is located at (8,5). what point partitions the directed line segment ab into a 1: 3 ratio
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Ответ:
point(3.5 , 7.25)
Step-by-step explanation:
Given in the question,
pointA(2,8)
pointB(8,5)
To find,
A point which partition AB into 1:3
x1 = 2
x2 = 8
y1 = 8
y2 = 5
a = 1
b = 3
Formula to use
x' = x1 + (a/a+b)(x2-x1)y' = y1 + (a/a+b)(y2-y1)Plug in the values
x' = 2 + (1/1+3)(8-2)
= 3.5
y' = 8 + (1/1+3)(5-8)
= 7.25
So, point(3.5 , 7.25) partitions the directed line segment AB into a 1:3 ratio
Ответ:
The point is (3.5 , 7.25)
Step-by-step explanation:
∵ A = (2 , 8) and B = (8 , 5)
∵ Let point P divides AB into a ratio 1:3
∵![x=\frac{m_{2}x_{1}+m_{1}x_{2}}{m_{1}+m_{2}}](/tpl/images/0296/2362/6e2fe.png)
∵![y=\frac{m_{2}y_{1}+m_{1}y_{2}}{m_{1}+m_{2}}](/tpl/images/0296/2362/6a8df.png)
∴ x-coordinate of P = (2)(3) + (8)(1)/3 + 1 = (6 + 8)/4 = 3.5
∴ y-coordinate of P = (8)(3) + (5)(1)/1 + 3 = (24 + 5)/4 = 7.25
∴ P = (3.5 , 7.25)
Ответ:
89
Step-by-step explanation:
idk honestly