Mathematics: Point j(-2,1) and point k(4,5) form line segment jk. for the point p that partitions jk in the ratio 3: 7, what is the y- coordinate of p?

Point j(-2,1) and point k(4,5) form line segment - id21451360920, xaniawashington

jahnoibenjamin

14.03.2022

If J(x_1,y_1) and K(x_2,y_2) are two points, then $P(\frac{nx_1+mx_2}{m+n},\frac{ny_1+my_2}{m+n})$ partitions JK in the ratio, m:n .

The y-coordinate of P is

$y=\frac{ny_1+my_2}{m+n}=\frac{7*1+3*5}{3+7}=\frac{11}{5}$

0,0(0 оценок)

Mikec123

14.03.2022

2.2

Step-by-step explanation:

We have been given that point J(-2,1) and point K(4,5) form line segment JK. The point P partitions JK in the ratio 3:7.

To find the y-coordinate of point P we will use section formula, when a point A divides a segment JK internally in the ratio m:n.

$[x=\frac{mx_2+nx_1}{m+n},y=\frac{my_2+ny_1}{m+n}]$

Upon substituting our given values in above formula we will get,

$[x=\frac{3*4+7*-2}{3+7},y=\frac{3*5+7*1}{3+7}]$

$[x=\frac{12-14}{10},y=\frac{15+7}{10}]$

$[x=\frac{-2}{10},y=\frac{22}{10}]$

[x=-0.2,y=2.2]

Therefore, the y-coordinate of point P is 2.2.

0,0(0 оценок)

live4dramaoy0yf9

19.11.2022

I think your answer 4 I'm not sure tho hope this helps

0,0(0 оценок)