Point p is the interior of angle abc. If angle abc=125deg and angle abp=62deg, what is the angle pbc?

The angle ∠ PBC is 63°.

Step-by-step explanation:

Given: Point P is in the interior of ∠ABC.

∠ ABC = 125°

∠ABP= 62°

To find : ∠ PBC

Since P is in the interior of ∠ABC.

Then

∠ ABC = ∠ABP + ∠ PBC

⇒ 125°= 62°+ ∠ PBC

⇒ ∠ PBC= 125° - 62°

⇒ ∠ PBC= 63°

Hence, the angle ∠ PBC is 63°.

This is an equation that has b multiplied by the value h/2. To get b by itself, multiply both sides of the equation by 2/h, the reciprocal of the coefficient of b.

2A/h = b