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3kp
29.05.2020 •
Mathematics
Point Q is equidistant from AB and AC. What must be true about Q?
Chose from the following
A. It's on the perpendicular bisector of AB
B. It's on the perpendicular bisector of AC
C. BQ=CQ
D. It is on the angle bisector of ∠BAC.
Solved
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Ответ:
D. It is on the angle bisector of ∠BAC
Step-by-step explanation:
Given that point Q is equidistant from AB and AC. This implies that AB and AC forms an angle BAC i.e <BAC. An equidistant point is a point that has the same distance from two different reference points.
Bisection is the process by which a line or angle is divided into two equal parts. A line that passes through the point of division is called a bisector, which is of equal distance to either of the reference points.
Thus by construction, a point that would be of equal distance to AB and AC is on an angle bisector of <BAC. So that point Q is on the angle bisector of <BAC.
Ответ:
Required function will be
Average rate of change will be $25 per month.
Step-by-step explanation:
Since we have given that
Eliza started her saving account with $100 .
So, Initial amount = $100
Each month she deposits $25 into her account ,
So, Increment per month = $25
Now, we need a relationship between the amount Eliza deposit and the total amount in her amount will be
So, required function will be
In Second month, amount will be
In tenth month, amount will be
Average rate of change from second month to the 10 th month will be
Hence, average rate of change will be $25 per month.