PR and os are diameters of circle T. What is the
measure of SR?
50°
* 80°
• 100°
120

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Ответ:

pineapplepizaaaaa

05.04.2020

Mathematics

The solutions are $x=4\sqrt{3}$ an $x=-4\sqrt{3}$

Step-by-step explanation:

We want to find the root of the quadratic function f(x)=x^2-48

To find the roots of this function, we set f(x)=0

This implies that:

x^2-48=0

This implies that:

x^2=48

Take square root to get;

$x=\pm \sqrt{48}$

$x=\pm4\sqrt{3}$

Therefore the solutions are $x=4\sqrt{3}$ an $x=-4\sqrt{3}$

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PR and os are diameters of circle T. What is the measure of SR? 50° * 80° • 100° 120