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tay9122

12.07.2022

Mathematics

we know that

RT=TQ -----> given problem

Applying the Pythagoras Theorem

In the right triangle RTS

$RS^{2}=RT^{2}+TS^{2}$

In the right triangle TQS

$QS^{2}=TQ^{2}+TS^{2}$

remember that

RT=TQ

therefore

RS=QS

substitute the values

(3x+2)=(5x-8)

solve for x

5x-3x=2+8

2x=10

$x=5\ units$

Find the value of segment QS

$QS=5x-8=5*5-8=17\ units$

The answer is

The length of segment QS is $17\ units$

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