Prove: An odd times an odd equals an odd.
(2m + 1)(2n + 1) = [ ? ]mn + ]m +[ ]n + [ ]
= 2([ ]mn + m + 1 + 1
= odd

Prove: An odd times an odd equals an

odd.
(2m + 1)(2n + 1) = [ ? ]mn + ]m +[ ]n + [ ]
= 2([ ]mn +

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Ответ:

derrishamckenzie22

01.07.2022

Mathematics

The curve is concave up when

Step-by-step explanation:

The given function is

$y=\frac{(1-x)}{(x-3)}$

To find where the function is concave up, we have to find the second derivative of the function.

The derivative of a fraction is

$(\frac{f(x)}{g(x)})' =\frac{g(x)f'(x)-g'(x)f(x)}{(g(x))^{2} }$

Where f(x)=1-x and g(x)=x-3 .

Using the property, we have

$y'=\frac{(x-3)(-1)-(1)(1-x)}{(x-3)^{2} } =\frac{-x+3-1+x}{(x-3)^{2} } =\frac{2}{(x-3)^{2} }$

Then, we repeat the process to find the secon derivative

$y''=\frac{(x-3)^{2}(0)-2(x-3)(1)(2) }{(x-3)^{4} } =\frac{-4(x-3)}{(x-3)^{4} }\\ y''=\frac{-4}{(x-3)^{3} }$

For a concave up inflection, we must evalute y''0

$y''=\frac{-4}{(x-3)^{3} }0 \implies (x-3)^{3}$

Therefore, the curve is concave up when .

In the image attached you can observe this behaviour.

The curve y= (1-x)/(x-3) is concave up when:

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Prove: An odd times an odd equals an odd. (2m + 1)(2n + 1) = [ ? ]mn + ]m +[ ]n + [ ] = 2([ ]mn + m + 1 + 1 = odd