Prove cosxtanx = sinx

Cos(x)tan(x)

Transform the expression by using the formula for tan theta:
tan(t)= sin(t)/cos(t)

cos(x)= sin(x)/cos(x)

Cancel out the cos(x) since it’s on both sides

Final answer : sin(x)

cos(x)tan(x) is equal to sin(x)

(x, y) -> (x + 1, y + 1), (x, y) -> (y, x)

Step-by-step explanation:

I'll use point B (-3,0) for this problem.

First, the translation rule tells us to add 1 to the x value and add 1 to the y value. Now we have (-2, 1). Next, the rule tells us to flip the x and y coordinates. Now we have (1, -2). This matches to vertex B''(1, -2).