hardwick744
08.09.2019 •
Mathematics
Prove that the two circles shown below are similar. circle c is shown with a center at negative 3, 1 and a radius of 4. circle e is shown with a center at 4,9 with a radius of 3.
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Ответ:
Step-by-step explanation:
Any two circles are similar!OK. I will prove it.
We must prove that there are two conditions:
1. The same shape (the corresponding angles are the same measure).
2. Corresponding lengths form a proportion.
1. Any two circles have the same shape.
2. We calculate the circumference of both circles.
The formula of a circumference of a circle:
r - radius
We have
Substitute:
The ratio of radiuses:
<p>The ratio of circumferences:</p><p>[tex]\dfrac{C_C}{C_E}=\dfrac{8\pi}{6\pi}=\dfrac{8}{6}=\dfrac{8:2}{6:2}=\dfrac{4}{3}" class="latex-formula" id="TexFormula4" src="https://tex.z-dn.net/?f=%5Cdfrac%7Br_C%7D%7Br_E%7D%3D%5Cdfrac%7B4%7D%7B3%7D%3C%2Fp%3E%3Cp%3EThe%20ratio%20of%20circumferences%3A%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Cdfrac%7BC_C%7D%7BC_E%7D%3D%5Cdfrac%7B8%5Cpi%7D%7B6%5Cpi%7D%3D%5Cdfrac%7B8%7D%7B6%7D%3D%5Cdfrac%7B8%3A2%7D%7B6%3A2%7D%3D%5Cdfrac%7B4%7D%7B3%7D" title="\dfrac{r_C}{r_E}=\dfrac{4}{3}</p><p>The ratio of circumferences:</p><p>[tex]\dfrac{C_C}{C_E}=\dfrac{8\pi}{6\pi}=\dfrac{8}{6}=\dfrac{8:2}{6:2}=\dfrac{4}{3}">
Both conditions are true. So the two circles are similar.Ответ:
3x+2/4 = 2x-1/3
x = -10
Step-by-step explanation: