JOEFRESH10
24.01.2020 •
Mathematics
Prove that there are no positive perfect cubes less than 1000 that are the sum of the cubes of two positive integers?
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Ответ:
1^3 = 1
2^3 = 8
3^3 = 27
4^3 = 64
5^3 = 125
6^3 = 216
7^3 = 343
8^3 = 512
9^3 = 729
so
2^3 = 8 could only be 1 + 1, but this is 2, not 8.
3^3 = 27 could be 1 + 1, 1 + 8 or 8 + 8, but all of these are too small
4^3 = 64 could be 1 + 1, 1 + 8, 1 + 27, 8 + 8, 8 + 27, 27 + 27.
general proof that a^3 + b^3 = c^3 holds for no positive integers
hope it helps
Ответ:
4−4(−2a−9)+10a
Distribute:
=4+(−4)(−2a)+(−4)(−9)+10a
=4+8a+36+10a
Combine Like Terms:
=4+8a+36+10a
=(8a+10a)+(4+36)
=18a+40
=18a+40