Provide an appropriate response. in a game, you have a 1/36 probability of winning $94 and a 35/36 probability of losing $8. what is your expected value

We can find this by adding together the probabilities times the values of each probability, so it's:
 EV=P1*V1+P2*V2
where
EV> is the expected value
P1> (1/36)
V1> $94
P2> (35/36)
V2> -$8

so
 EV=(1/36)*94+(35/36)*(-8)> (94/36)+(-280/36)> -186/36---> -5.17

EV=-$5.17

the answer is
the expected value is EV=-$5.17

rwqfWQFwqgwWGWEGEWGWGWEG