Mathematics: Q5) given that f(x) = x^2 + x and g(x) = 3x + 1, find the value of f(g(4))

Q5) given that f(x) = x^2 + x and g(x) = 3x +

jaejaeJae941

09.02.2022

169

Step-by-step explanation:

3(4)+1

=12+1

=13

f(g(4))

f(x)=x^2 (13)^2

=13x13

=169

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bre2795

21.12.2022

Step-by-step explanation:

We can use the distance formula derived from the Pythagorean theorem

D = $\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

the two points given are

(0, 3) and (-2, -3)

$(x_2-x_1) = (0-(-2)) = 2\\(y_2-y_1) = (3-(-3)) = 6\\D = \sqrt{(2)^2 + (6)^2} \\D = \sqrt{4 + 36} \\D = \sqrt{40} = 6.324$

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