Quadrilateral ABCD is inscribed in a circle. What is the measure of

angle A?

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M

A+5(2a-1)+3=11a-2
First thing to do is distribute
5*2a=10a
5*-1=-5
a+10a-5=11a-2
Add the similar numbers together
11a-5=11a-2
Then subtract 
11a-11a
-5=-2
This equation has no solutions
If it had infinity solutions then both numbers on each side would equal the same, ex: -5=-5