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thomasbarbusca15
16.02.2020 •
Mathematics
Quadrilateral PQRS is a square whos side length is 10. Let X and Y be points outside the square so that XQ = YS = 6 and XP = YR = 8. Find XY^2.
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Ответ:
392
Step-by-step explanation:
Triangles XQP and YRS are right triangles because triples 6, 8, 10 are Pythagorean triples.
Extend lines XQ, YR, YS and XP and mark their intersection as A and B.
Quadrilateral XAYB is a square because all right triangles PXQ, QAR, RYS and SBP are congruent (by ASA postulate) and therefore
all angles of the quadrilateral XAYB are right angles all sides of XAYB are congruent and equal to 6 + 8 = 14 units.Segment XY is the diagonal of the square XAYB, by Pythagorean theorem,
Ответ:
Diameter is twice the amount of the radius
Step-by-step explanation: