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jltijinotgion121
02.02.2020 •
Mathematics
Quadrilateral wxyz is located at w(2,1), x(5,2), y(4, 4), z(2,4) and is translated to quadrilateral w’x’y’z’ at w’(-2, -2), x’(1, -1), y’(1, 1), z’(-2, 1) by moving three units to the right and four units to up.
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Ответ:
False
Step-by-step explanation:
3 units to the right and 4 units up represents adding 3 to the original x- coordinate and adding 4 to the original y- coordinate, that is
(x, y ) → (x + 3, y + 4 ) ← translation rule
Applying this rule to the given points
W(2, 1 ) → W'(2 + 3, 1 + 4 ) → W'(54, 5 ) ≠ (- 2, - 2 )
X(5, 2 ) → X'(5 + 3, 2 + 4 ) → X'(8, 6 ) ≠ (1, - 1 )
Y(4, 4 ) → Y'(4 + 3, 4 + 4 ) → (7, 8 ) ≠ (1, 1 )
Z(2, 4 ) → Z'(2 + 3, 4 + 4 ) → Z'(5, 8 ) ≠ (- 2, 1 )
Ответ:
just replace all x's with x+5 in first equation
f(x+5)=(x+5)^2+3(x+5)-10
f(x+5)=x^2+10x+25+3x+15-10
f(x+5)=x^2+13x+30
compare
f(x)=x^2+3x-10
f(x+5)=x^2+13x+30
now we can set it to zero
f(x+5)=0
0=x^2+13x+30
factor
0=(x+3)(x+10)
set each to zero
x+3=0
x=-3
x+10=0
x=-10
-10<-3
smalles zero is x=-10