Mathematics: Question 20(Multiple Choice Worth 2 points) (01.02 LC) Which number has a 9 that is one tenth the value of the 9 in 296? 195 409 981 1,956 NO LINKS HELP ASAP

Assuming the problem as stated is, givenfind .Provided that is (at least locally) invertible, we have , and differentiating both sides with respect to givesNotice that , which means . From this it follows thatand since by the fundamental theorem of calculus, it follows that , and so ....

Question 20(Multiple Choice Worth 2 points) (01.02

Ответ:

hollisjune3047

22.04.2021

Mathematics

409 i would say

Step-by-step explanation:

very sorry is its wrong!!! :(

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Ответ:

liz77717

22.04.2021

Mathematics

prob a im guessing :^)

Step-by-step explanation:

tell me if i got it right or wrong i will fix if needed

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Ответ:

topangabraith

21.07.2022

Mathematics

Assuming the problem as stated is, given

$f(x)=\displaystyle\int_3^x\sqrt{1+t^3}\,\mathrm dt$

find $(f^{-1})'(0)$ .

Provided that

is (at least locally) invertible, we have $f(f^{-1}(x))=x$ , and differentiating both sides with respect to

gives

$f'(f^{-1}(x))(f^{-1})'(x)=1\implies (f^{-1})'(x)=\dfrac1{f'(f^{-1}(x))}$

Notice that f(3)=0

, which means $f^{-1}(0)=3$ . From this it follows that

$(f^{-1})'(0)=\dfrac1{f'(f^{-1}(0))}=\dfrac1{f'(3)}$

and since $f'(x)=\sqrt{1+x^3}$ by the fundamental theorem of calculus, it follows that $f'(3)=2\sqrt7$ , and so $(f^{-1})'(0)=\dfrac1{2\sqrt7}$ .

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Question 20(Multiple Choice Worth 2 points) (01.02 LC) Which number has a 9 that is one tenth the value of the 9 in 296? 195 409 981 1,956 NO LINKS HELP ASAP

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