musa79
26.11.2021 •
Mathematics
Question 3 What is the equation of the parabola that opens up, has a vertex V(5,0), and a y-intercept of 50?
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Ответ:
y=2(x-5)^2
Step-by-step explanation:
Vertex form:
y=a(x-p)^2+q
(p,q) = (5,0)
y=a(x-5)^2
y-intercept has coordinates (0,50) so, substitute x=0 and y= 50 in the above equation to find "a"
50=a(0-5)^2
50=25a
a=2
equation
y=2(x-5)^2
Ответ: