Mathematics: Question in image :)

Question in image :) - id9771494, nuclearfire278

jdeelc

28.08.2020

$P(\frac{10}{3}, \frac{-2}{3})$

Step-by-step explanation:

The question is incomplete; However

A = (-2, -4)

B = (6, 1)

Required

Determine coordinates of P

When line segment is divided in ratios, the following formula calculates the coordinates;

$P(x,y) = \{\frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n}\}$

In this case;

m:n = 2:1

(x_1,y_1) = (-2, -4)

(x_2,y_2) = (6, 1)

So, the coordinates of P is calculated as thus

$P(x,y) = \{\frac{2 * 6 + 1 * (-2)}{2+1}, \frac{2 * 1 + 1 * (-4)}{2+1}\}$

$P(x,y) = \{\frac{12 -2}{3}, \frac{2 -4}{3}\}$

$P(x,y) = \{\frac{10}{3}, \frac{-2}{3}\}$

Hence, the coordinates of P is

$P(\frac{10}{3}, \frac{-2}{3})$

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