QUICKLY PLEASE NO LINKS! Kyle has been trying to improve the speed of his tennis serve. His coach points out the need to emphasize weight transfer during the serve motion. How can Kyle best achieve this weight transfer? Hold his racquet further away from his body Hold his racquet with the non-dominant hand Shift his weight from the back foot to the front foot while striking the ball Shift his weight from the front foot to the back foot while striking the ball

(Option b): segment BC = segment B double prime C double prime over 3

A complete question related to this found at (ID: 13432500) is stated below:

Triangle A″B″C″ is formed using the translation (x + 1, y + 1) and the dilation by a scale factor of 3 from the origin. Which equation explains the relationship between segment BC and segment B double prime C double prime? coordinate plane with triangle ABC at A negative 3 comma 3, B 1 comma negative 3, and C negative 3 comma negative 3

a) segment B double prime C double prime = segment BC over 3

b) segment BC = segment B double prime C double prime over 3

c) segment B double prime C double prime over segment BC = one third

d) segment BC over segment B double prime C double prime = 3

Step-by-step explanation:

Scale factor = 3

∆ABC = original image

∆ABC was dilated to get ∆A"B"C"

∆A"B"C" = new image

DO(x,y) →3(x,y)

To determine which equation explains the relationship between segment BC and segment B"C", first we would find the distance B and C.

Coordinates of ∆ABC

A =(-3, 3)

B= (1, -3)

C= (-3, -3)

The distance B and C = length of Segment BC

the distance between two points = √[(∆x)² + (∆y)²]

= √[(-3-(-3))² + (-3-1)²] = √[(-3+3)² + (-3-1)²]

= √(0+16) = √16 = 4

Length of Segment BC = 4 units

Length of Segment B"C" = scale factor × Length of Segment BC

B"C" = 3 × BC = 3(4) = 12

Since what we need is the equation of the relationship between the segments

B"C" = 3 × BC

BC = B"C"/3

(Option b): segment BC = segment B double prime C double prime over 3