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libertycooper
18.07.2019 •
Mathematics
Raj wrote the four equations that are shown below. a 3(x+4)=3(x+2)+6 b 6(x-1)=3(x-1)+3 c 5x+4-x=2(2x-2) d -2(x+3)+x=-x-6 he examined them, without solving them, to determine which has no solution. which of raj’s equations has no solution?
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Ответ:
Step-by-step explanation:
When a equation has no solution is because, inevitably, the variable gets eliminated. So, to find the answer to this question, we have to solve each of them
Option A.As you can see, this equation is the one that doesn't have one solution, it actually have infinite solutions, because we got a true statement 0=0.
Option B.![6(x-1)=3(x-1)+3\\6x-6=3x-3+3\\6x-3x=6\\3x=6\\x=2](/tpl/images/0103/8316/b2eb6.png)
Option C.We know that this result is false, this means the equation has no solutions, because it ended in a false statement.
Option D.It's the same as option A, this equation has infinite solutions.
Therefore, the equation that has no solution is C, because it ends in a false statement.
Ответ:
The answer is B 1.20x + 2.5 < 20
Step-by-step explanation:
I am on Edge. and I got it right :)
**It wont let me spell the full word sorry**