Ashtree519
19.07.2019 •
Mathematics
Range of y=sqrt(10-3x) algebraically
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Ответ:
Ответ:
x = 11.31
y = 13.86
z = 19.60
Step-by-step explanation:
8/x = x/16
x^2 = 128
x = 11.31
x^2 + 8^2 = y^2
128 + 64 = y^2 = 192
y = 13.86
x^2 + 16^2 = z^2
128 + 256 = z^2
z^2 = 384
z = 19.60