Mathematics: Rearrange the formula v = 2πr/t for r. a)r = π/2tv b)r = 2π/tv c) r = 2tv/π d) r = tv/2π

Rearrange the formula v = 2πr/t for r. a)r = π/2tv

Ответ:

michaeldragon9663

14.03.2022

Mathematics

Option D.

Step-by-step explanation:

The given volume formula is

$V=\frac{2\pi r}{T}$

We need to rearrange the given formula for r. It means we have to isolate variable r.

Multiply both sides by T.

$V\times T=\frac{2\pi r}{T}\times T$

$VT=2\pi r$

Divide both sides by 2π.

$\frac{VT}{2\pi }=\frac{2\pi r}{2}$

$\frac{VT}{2\pi }=r$

Interchange the sides.

$r=\frac{VT}{2\pi }$

The formula for r is $r=\frac{VT}{2\pi }$ .

Therefore, the correct option is D.

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Ответ:

Maddi7328

11.05.2023

Mathematics

$\boxed{\textsf{ The lenght of segment is \textbf{ 10}$\sqrt{\textbf{2}} $ \textbf{ units }.}}$

Step-by-step explanation:

We need to find the lenght of the segment drawn from (-5,2) to (5,-8) . Basically here we need to find the distance between the two points .

Here we can use Distance Formula , which is used to find the distance between two points .

$\rule{200}2$

★ Distance Formula :-

If we need to find the distance between two points say , $\sf ( x_1,y_1 ) \:\:\:\: \& \:\:\:\: ( x_2,y_2)$ , then we can find out the distance as ,

$\boxed{\boxed{ \sf Distance =\sqrt{ ( x_2-x_1)^2+(y_2-y_1)^2 } }}$

$\rule{200}2$

Put on the respective values ,

$\sf\implies Distance =\sqrt{ ( x_2-x_1)^2+(y_2-y_1)^2 } \\\\\sf\implies Distance =\sqrt{ ( -5-5)^2+(2+8)^2 }\\\\\sf\implies Distance= \sqrt{ (-10)^2+(10)^2 }\\\\\sf\implies Distance =\sqrt{ 100+100}\\\\\sf\implies Distance =\sqrt{200}\\\\\sf\implies Distance =\sqrt{2\times 10\times 10}\\\\\sf\implies \boxed{\pink{\frak{ Distance = 10\sqrt{2} \:\; units }}}$

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Rearrange the formula v = 2πr/t for r. a)r = π/2tv b)r = 2π/tv c) r = 2tv/π d) r = tv/2π

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