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29.01.2020 •
Mathematics
Rectangle a has a length of 80 inches and a width of 30 inches. rectangle a has the same area as rectangle b, but has different dimensions. the width of rectangle b is 80% shorter than the width of rectangle a as shown. which percent represents how much longer the length of rectangle b must be to maintain the same area as rectangle a?
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Ответ:
The length of rectangle B must to be 25% greater than the length of rectangle A
Step-by-step explanation:
step 1
Find the area of rectangle A
substitute the given values
step 2
Find the width of rectangle B
Multiply by 0.80 (80%) the width of rectangle A
step 3
Find the length of rectangle B
we have
substitute in the formula of area
solve for L
step 4
Find the percentage
we know that
The length of rectangle A represent 100%
so
using proportion
Find out what percentage represent the difference of its length
100-80=20 in
therefore
The length of rectangle B must to be 25% greater than the length of rectangle A
Ответ:
42
Step-by-step explanation:
Area = length ×width
? = 6×7
42 = 6×7