Renee has dimes and quarters in her wallet that total

Ответ:

nestergurl101

10.07.2021

Given:

Renee has dimes and quarters in her wallet that total $1.60.

She has 2 more dimes than quarters.

To find:

The number of each type of coins.

Solution:

Let x be the number of dimes and y be the number of quarters.

She has 2 more dimes than quarters. So,

x=y+2 ...(i)

We know that,

1 dime = $0.10

1 quarter = $0.25

Renee has dimes and quarters in her wallet that total $1.60. So,

0.10x+0.25y=1.60 ...(ii)

From (i) and (ii), we get

0.10(y+2)+0.25y=1.60

0.10y+0.20+0.25y=1.60

0.35y=1.60-0.20

0.35y=1.40

Divide both sides by 0.35.

$y=\dfrac{1.40}{0.35}$

y=4

Substituting y=4 in (i), we get

x=4+2

x=6

Therefore, the number of dimes is 6 and the number of quarters is 4.

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