Rewrite 1/(tanX + cotX) so it’s not in fractional form

X+ 2 =  √(3x + 10)
in the form:
x + a =  √(bx + c)

if we let x = 7
7 + a =  √(7b + c)
squaring both sides
7 + 14a + a² = 7b + c

assume a = 1
7 + 14 + 1 = 7b + c
22 = 7b + c
assume a = 2
39 = 7b + c

there are no solutions to the the two equations.